Please someone help with the reduction of silver ion in the process of silver bottles.?
With a clean glass bottle, a solution aqueous sucrose (A), an aqueous solution of silver nitrate (B) and an aqueous solution of sodium hydroxide (C), silver glass bottles due to a redox reaction that occurred. A glass bottle is cleaned and then three pipette solutions A, B and C were added to it and gently swirled, resulting in a silver flask. That is the essence of my experiment. What's inside the bottle is covered with silver? I understand that due to a redox reaction. 1. What substance is reduced in reaction (I think it is Ag +), 2. Write the reaction that produces the above reduction. 3. What compound is oxidixed (this is the sucrose so how does this reaction)? I understand some of the lab, but I can not determine the equation written with the actual change of oxidation numbers. If anyone could provide that to me (possibly both oxidation and reduction by half), that would be awesome. Thanks!
Ok, sucrose is a dimer composed of one molecule of glucose (or dextrose, if you prefer) and one fructose. Glucose is an aldehyde, while fructose is a ketone. The active portion of the reduction reaction is the aldehyde of glucose molecule, and more specifically, the hydrogen atom on the end of the aldehyde is what is reduced to form glucuronic acid, or more precisely, sodium glucuronate. The reaction is as follows: C6H12O6 (glucose) +2 AgNO3 3 NaOH => NaC6H11O7 2 2 2 H2O NaNO3 Ag'll let you make the redox, as this is the task, right? Hope this helps. Oops, just noticed a mistake in my equation, but it fixed now. See above. PS For some reason, Yahoo will not let me answer your emails.
Viscosity Measurement using Ostwald’s Viscometer (Amrita University)
